C++ Program to Check Leap Year
This program check given number is year leap or not.You must have basic knowledge of C++ programming language and variable , while loop and if..ealse and for loop
Leap year that is given number divided by
4.if number is perfectly divided to 4 its also
known as leap year.
leap year such as 2004,2008,2012,2016,2020
2024,2028
Example: Check given a year is leap year or not
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int y;
cout << "Plz Enter a year: ";
cin >> y;
if (y % 4 == 0)
{
if (y % 100 == 0)
{
if (y % 400 == 0)
cout << y << " leap year.";
else
cout << y << "not leap year.";
}
else
cout << y << " leap year.";
}
else
cout << y << " not leap year.";
return 0;
}
Output
Plz Enter a year: 2012
2012 leap year.
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